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Published on 2010-04-30T21:06:36Z
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2010/04/30
21:17 UTC
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What are local and global variables?
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I ran this command
sudo find / -type d -name '*Trash*' | sudo xargs du -h | sort
This was the output:
100M /root/.local/share/Trash/files/recup_dir.2.30
100M /root/.local/share/Trash/files/recup_dir.2.72
100M /root/.local/share/Trash/files/recup_dir.32
101M /root/.local/share/Trash/files/recup_dir…
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I'm trying to install ModSecurity on nginx with the following instructions :
wget https://github.com/SpiderLabs/ModSecurity/archive/master.zip
unzip master
cd ModSecurity-master
./autogen.sh
./configure --enable-standalone-module
And i got the following error :
Checking plataform... Identified…
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I couldn't install mysql I get this
brew install mysql
Error: You must `brew link cmake' before mysql can be installed
so then I type brew ink cmake …
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Mailman is giving off this error when any changes are made to the list:
=======================
Bug in Mailman version 2.1.14
We're sorry, we hit a bug!
Please inform the webmaster for this site of this problem. Printing of traceback and
other system information has been explicitly…
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I know it is probably not necessary to paste the whole path, but just for the record I have done so below. Whenever I run a python command, it takes a long time to load this path I suppose. I have checked in .bash_profile and only have these two lines:
export PATH=/Users/username/bin:/opt/local/Library/Frameworks/Python…
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I have set an array in my config file that I use global in my functions.
This works fine, but now I want to pass the name of this array as a @param in my function.
// in config file:
$album_type_arr = array("appartamento", "villa");
global $album_type_arr; // pull in from db_config
echo $album_type_arr[0];
function…
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I have a tricky one.
By means of a <cfoutput query="…"> I list some records in the page from a SQL Server database.
By the end of each line viewing I try to add this in to a record in a MySQL database.
As you see is simple, because I can use the exact variables from the output query in to…
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One of the very tricky question asked in an interview...
we need to swap the values of two variables like a=10 and b=15
Generaly to swap two variables values, we need 3rd variable like..
temp=a
a=b
b=temp
Now the requirement is, swaping value of two variable values without using 3rd variable…
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Hey guys...
$bookA = "123";
$crack = "A";
I want to do something similar to this:
echo $book$crack;
Such that the output is 123.
What is the correct syntax for the echo command?
Thanks.
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is it possible to copy a variable like this this?
class Colours {
var $var = "one";
var $var2 = array('something', $var);
}
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