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I have an instance of dict with ints, floats, strings as keys, but the problem is when there are a as int and b as float, and float(a) == b, then their hash values are the same, and thats what I do NOT want to get because I need unique hash vales for this cases in order to get corresponding values…
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What property makes Hash table, Hash list and Hash tree different from each other? Which one is used when? When is table superior than tree.
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Hi, I would like to construct a hash table that looks up keys in sequences (strings) of bytes ranging from 1 to 15 bytes.
I would like to store an integer value, so I imagine an array for hashing would suffice. I'm having difficulty conceptualizing how to construct a hash function such that given…
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Theoretically does hashing a unique value yield a unique value?
Let's say I have a DB table with 2 columns: id and code. id is an auto-incrementing int and code is a varchar. If I do ...
$code = sha1($id);
... and then store $code into the same row as $id. Will my code column be unique as well…
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I attempted to install the perl module Net::Twitter::Role::API::Lists using WHM and after doing so my whole site came down. It seems that something that was updated with the install isn't functioning correctly and since our website it written in Perl none of our site scripts will run.
In almost 8…
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There are some programs which can display used disk space using a treemap, such as WinDirStat for Windows and KDirStat for KDE/Linux:
I'm looking for something similar, but for a headless Linux box.
Alternatively, what are other good ways to visualize used disk space with just SSH access?
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I have the following TreeMap:
TreeMap<String, Integer> distances = new TreeMap<String, Integer>();
and it contains both strings, "Face" and "Foo", with appropriate values, such that:
System.out.println(distances);
Yields:
{Face=12, Foo=2}
However, distances.get(Face) returns…
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I have the following TreeMap:
TreeMap<String, Integer> distances = new TreeMap<String, Integer>();
and it contains both strings, "Face" and "Foo", with appropriate values, such that:
System.out.println(distances);
Yields:
{Face=12, Foo=2}
However, distances.get(Face) returns…
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I'm switching from scala 2.7 and ordered to scala 2.8 and using ordering. It looks quite straight forward but I was wondering could I make it a little less verbose. For example:
scala> case class A(i: Int)
defined class A
scala> object A extends Ordering[A] { def compare(o1: A, o2: A) = o1…
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I have the following object Node:
private class Node implements Comparable<Node>(){
private String guid();
...
public boolean equals(Node o){
return (this == o);
}
public int hashCode(){
return guid.hashCode();
}
...
}
And I use it…
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