Does "opening a file" mean loading it completely into memory?

Posted by mystify on Stack Overflow See other posts from Stack Overflow or by mystify
Published on 2010-05-01T13:03:14Z Indexed on 2010/05/01 13:07 UTC
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There's an AudioFileOpenURL function which opens an file. With AudioFileReadPackets that file is accessed to read packets. But one thing that stucks in my brain is: Does AudioFileOpenURL actually load the whole monster into memory? Or is that a lightweight operation?

So is it possible to read data from a file, only a specific portion, without having the whole terabytes of stuff in memory?

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Does "opening a file" mean loading it completely into memory?

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