Figure out if element is present in multi-dimensional array in python
Posted
by Terje
on Stack Overflow
See other posts from Stack Overflow
or by Terje
Published on 2010-05-01T20:44:12Z
Indexed on
2010/05/01
20:47 UTC
Read the original article
Hit count: 338
I am parsing a log containing nicknames and hostnames. I want to end up with an array that contains the hostname and the latest used nickname.
I have the following code, which only creates a list over the hostnames:
hostnames = []
# while(parsing):
# nick = nick_on_current_line
# host = host_on_current_line
if host in hostnames:
# Hostname is already present.
pass
else:
# Hostname is not present
hostnames.append(host)
print hostnames
# ['[email protected]', '[email protected]', '[email protected]']
I thought it would be nice to end up with something along the lines of the following:
# [['[email protected]', 'John'], ['[email protected]', 'Mary'], ['[email protected]', 'Joe']]
My problem is finding out if the hostname is present in such a list
hostnames = []
# while(parsing):
# nick = nick_on_current_line
# host = host_on_current_line
if host in hostnames[0]: # This doesn't work.
# Hostname is already present.
# Somehow check if the nick stored together
# with the hostname is the latest one
else:
# Hostname is not present
hostnames.append([host, nick])
Are there any easy fix to this, or should I try a different approach? I could always have an array with objects or structs (if there is such a thing in python), but I would prefer a solution to my array problem.
© Stack Overflow or respective owner