Passing array to function with pointer loses array size information!
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by Narek
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Published on 2010-05-01T09:38:58Z
Indexed on
2010/05/01
9:47 UTC
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If I write
int main()
{
int a[100] = {1,2,3,4,};
cout<<sizeof(a)/sizeof(a[0])<<endl;
return 0;
}
I get 400!
If I write
void func(int *a);
int main()
{
int a[100] = {1,2,3,4,};
func(a);
return 0;
}
void func(int *a)
{
cout<<sizeof(a)/sizeof(a[0])<<endl;
}
Then I get 400!
So why passing array to function with pointer loses array size information?
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