public String shorthand(String in)

Posted by luvthug on Stack Overflow See other posts from Stack Overflow or by luvthug
Published on 2010-05-03T19:52:08Z Indexed on 2010/05/03 19:58 UTC
Read the original article Hit count: 130

Filed under:

Hi All,

I am stuck on this code.

The code should use the class StringBuilder to build an output string by appending non-vowel characters from its argument in to the result it returns. It needs to identify vowels to be removed using the helper metod i created which is public boolean isVowel(char c).

public String shorthand(String in) this is the method I need help with. I have created the stringbuilder but the if condition does not accept isVowel method.

import java.io.*;
import java.util.*;


public class Shorthand
{    

    public boolean isVowel(char c)
   {

       if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' || c == 'A'|| c == 'E'||c == 'I'|| c == 'O'|| c == 'U')
       {
           return true;
       }
       else
       {
           return false;
       }
   }

    //TODO Complete the shorthand method
    public String shorthand(String in) //this is the code I need help with
    {
      StringBuilder vowel = new StringBuilder();

      if (isVowel() == false)strong text
      { 
        vowel.append(in); 
       } 
          return vowel.toString(); 
    }

    //TODO Complete the run method
    public void run() throws IOException
    {
       String yourLine; 
       Scanner sc = new Scanner(System.in); 
       yourLine = sc.nextLine(); 
       while(!yourLine.equals("*"));
       {
            System.out.println("Enter your line of text");
       }
       yourLine = sc.nextLine(); 
    }
}

© Stack Overflow or respective owner

Related posts about java