Replace always replacing null values
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by Mike
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Published on 2010-05-03T18:50:16Z
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2010/05/03
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sql-server-2000
Why does
left(FIELD, replace(nullif(charindex('-', FIELD), 0), null, len(FIELD)))
always return null? The idea behind the query is that if charindex() returns 0, then convert the results into null, then convert the null into the length of the field. So if '-' does not exist, show the whole string. For some reason it makes every row equal null.
Thank you.
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