Counting number of searches

Posted by shinjuo on Stack Overflow See other posts from Stack Overflow or by shinjuo
Published on 2010-05-04T19:27:09Z Indexed on 2010/05/04 19:38 UTC
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I am trying to figure out how to get the total number of tests each search makes in this algorithm. I am not sure how I can pass that information back from this algorithm though. I need to count how many times while runs and then pass that number back into an array to be added together and determine the average number of test.

main.c

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <stdbool.h>
#include "percentage.h"
#include "sequentialSearch.h"

#define searchAmount 100

int main(int argc, char *argv[])
{
  int numbers[100];
  int searches[searchAmount];
  int i;
  int where;
  int searchSuccess;
  int searchUnsuccess;
  int percent;

  srand(time(NULL));
  for (i = 0; i < 100; i++){
      numbers[i] = rand() % 200;
  }
  for (i = 0; i < searchAmount; i++){
      searches[i] = rand() % 200;
  }
  searchUnsuccess = 0;
  searchSuccess = 0;
  for(i = 0; i < searchAmount; i++){
        if(seqSearch(numbers, 100, searches[i], &where)){
              searchSuccess++;       
        }else{
              searchUnsuccess++;
        }
  }
  percent = percentRate(searchSuccess, searchAmount);
  printf("Total number of searches: %d\n", searchAmount);
  printf("Total successful searches: %d\n", searchSuccess);
  printf("Success Rate: %d%%\n", percent);

  system("PAUSE");  
  return 0;
}

sequentialSearch.h

bool seqSearch (int list[], int last, int target, int* locn){
     int looker;

     looker = 0;
     while(looker < last && target != list[looker]){
                  looker++;
     }

     *locn = looker;
     return(target == list[looker]);
}

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