Initialization of an ArrayList in one line.
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by Macarse
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Published on 2009-06-17T04:10:20Z
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2010/05/04
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I am willing to create a list of options to test something.
I was doing:
ArrayList<String> places = new ArrayList<String>();
places.add("Buenos Aires");
places.add("Córdoba");
places.add("La Plata");
I refactor the code doing:
ArrayList<String> places = new ArrayList<String>(Arrays.asList("Buenos Aires", "Córdoba", "La Plata"));
Is there a better way of doing this?
Thanks for reading!
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