Source operator doesn't work in if construction in bash

Posted by Igor on Stack Overflow See other posts from Stack Overflow or by Igor
Published on 2010-05-04T12:32:43Z Indexed on 2010/05/04 12:38 UTC
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Filed under:

bash

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include

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if

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source

Hello,

I'd like to include a config file in my bash script with 2 conditions: 1) the config file name is constructed on-the-fly and stored in variable, and 2) in case if config file doesn't exist, the script should fail:

config.cfg:

 CONFIGURED=yes

test.sh:

#!/bin/sh
$CFG=config.cfg

echo Source command doesn't work here:
[ -f $CFG ] && ( source $CFG ) || (echo $CFG doesnt exist; exit 127)
echo $CONFIGURED

echo ... but works here:
source $CFG
echo $CONFIGURED

What's wrong in [...] statement?

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