Why don't copy this dokument attributes from the source xml file??

Posted by siegfried storr on Stack Overflow See other posts from Stack Overflow or by siegfried storr
Published on 2010-05-04T08:13:25Z Indexed on 2010/05/04 8:18 UTC
Read the original article Hit count: 273

Filed under:
|

Hi anyone, i'm working the first time with xslt and i really don't understand why this xsl don't copy attributes from the source xml. Perhaps someone can give me a hint??

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output omit-xml-declaration="yes" indent="yes"/>
   <xsl:variable name="rpl" select="document('ParamInvoice.xml')"/>
   <xsl:template match="/">
      <xsl:copy>
         <xsl:apply-templates select="* | @*"/>
      </xsl:copy>
   </xsl:template>
   <xsl:template match="*">
      <xsl:variable name="vInvoiceElement" select="$rpl/StoraInvoice/*[name()=name(current())]"/>
      <xsl:copy>
         <xsl:if test="$vInvoiceElement/Attribute">
            <xsl:call-template name="AttributeErzeugen">
               <xsl:with-param name="pAttr" select="$vInvoiceElement/Attribute"/>
            </xsl:call-template>
         </xsl:if>
         <xsl:apply-templates/>
      </xsl:copy>
   </xsl:template>
   <xsl:template name="AttributeErzeugen">
      <xsl:param name="pAttr"/>
      <xsl:for-each select="$pAttr">
         <xsl:attribute name="{@name}"><xsl:value-of select="."/></xsl:attribute>
      </xsl:for-each>
   </xsl:template>
</xsl:stylesheet>

© Stack Overflow or respective owner

Related posts about xslt

Related posts about attribute