WPF MVVM UserControl Binding "Container", dispose to avoid memory leak.

Posted by user178657 on Stack Overflow See other posts from Stack Overflow or by user178657
Published on 2010-05-04T17:51:24Z Indexed on 2010/05/04 18:18 UTC
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For simplicity. I have a window, with a bindable usercontrol

<UserControl Content="{Binding Path = BindingControl, UpdateSourceTrigger=PropertyChanged}">

I have two user controls, ControlA, and ControlB, Both UserControls have their own Datacontext ViewModel, ControlAViewModel and ControlBViewModel.

Both ControlAViewModel and ControlBViewModel inh. from a "ViewModelBase"

public abstract class ViewModelBase : DependencyObject, INotifyPropertyChanged, IDisposable........

Main window was added to IoC... To set the property of the Bindable UC, i do

ComponentRepository.Resolve<MainViewWindow>().Bindingcontrol= new ControlA;

ControlA, in its Datacontext, creates a DispatcherTimer, to do "somestuff"..

Later on., I need to navigate elsewhere, so the other usercontrol is loaded into the container

ComponentRepository.Resolve<MainViewWindow>().Bindingcontrol= new ControlB

If i put a break point in the "someStuff" that was in ControlA's datacontext. The DispatcherTimer is still running...

i.e. loading a new usercontrol into the bindable Usercontrol on mainwindow does not dispose/close/GC the DispatcherTimer that was created in the DataContext View Model...

Ive looked around, and as stated by others, dispose doesnt get called because its not supposed to...

:)

Not all my usercontrols have DispatcherTimer, just a few that need to do some sort of "read and refresh" updates./.

Should i track these DispatcherTimer objects in the ViewModelBase that all Usercontrols inh. and manually stop/dispose them everytime a new usercontrol is loaded? Is there a better way?

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