shell_exec() Doesn't Show The Output
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by Nathan Campos
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Published on 2010-05-05T17:32:00Z
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2010/05/05
17:38 UTC
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I'm doing a PHP site that uses a shell_exec() function like this:
$file = "upload/" . $_FILES["file"]["name"];
$output = shell_exec("leaf $file");
echo "<pre>$output</pre>";
Where leaf is a program that is located in the same directory of my script, but when I tried to run this script on the server, I just got nothing. What is wrong?
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