Function to convert a z-score into a percentage

Posted by Daniel on Stack Overflow See other posts from Stack Overflow or by Daniel
Published on 2010-05-06T15:29:23Z Indexed on 2010/05/06 15:38 UTC
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Google doesn't want to help!

I'm able to calculate z-scores, and we are trying to produce a function that given a z-score gives us a percent of the population in a normal distribution that would be under that z-score. All I can find are references to z-score to percentage tables.

Any pointers?

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