Invalid URI: The Uri scheme is too long

Posted by phenevo on Stack Overflow See other posts from Stack Overflow or by phenevo
Published on 2010-05-07T09:48:58Z Indexed on 2010/05/07 10:48 UTC
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Hi,

I have XML:

Which is result of this part of query:

SELECT     Countries.FileSystemName as country ,Regions.DefaultName as region ,Provinces.DefaultName as province,cities.defaultname as city,cities.code as cityCode, IndividualFlagsWithForObjects.value as Status

I have xslt:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="text" encoding="iso-8859-1"/>

  <xsl:param name="delim" select="string(',')" />
  <xsl:param name="quote" select="string('&quot;')" />
  <xsl:param name="break" select="string('&#xD;')" />

  <xsl:template match="/">
    <xsl:apply-templates select="results/countries" />
  </xsl:template>

  <xsl:template match="countries">
    <xsl:apply-templates />
    <xsl:if test="following-sibling::*">
      <xsl:value-of select="$break" />
    </xsl:if>
  </xsl:template>

  <xsl:template match="*">
    <!-- remove normalize-space() if you want keep white-space at it is -->
    <xsl:value-of select="concat($quote, normalize-space(.), $quote)" />
    <xsl:if test="following-sibling::*">
      <xsl:value-of select="$delim" />
    </xsl:if>
  </xsl:template>

  <xsl:template match="text()" />
</xsl:stylesheet>

And is part of code

XmlReader reader = cmd.ExecuteXmlReader();

                    doc.LoadXml("<results></results>");


                    XmlNode newNode = doc.ReadNode(reader);

                    while (newNode != null)
                    {
                        doc.DocumentElement.AppendChild(newNode);
                        newNode = doc.ReadNode(reader);
                    }                    

                    doc.Save(@"c:\listOfCities.xml");

                    XslCompiledTransform XSLT = new XslCompiledTransform();

                    XsltSettings settings = new XsltSettings();

                    settings.EnableScript = true;


                    XSLT.Load(@"c:\xsltfile1.xslt", settings, new XmlUrlResolver());

                    XSLT.Transform(doc.OuterXml,@"c:\myCities.csv"); <-here I get error

Why I get error. Is seems to be good .

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