Why and how does dereferencing a function pointer just "do nothing"?

This is what I am talking about:

#include<stdio.h>

void hello() { printf("hello"); }

int main(void) { 
    (*****hello)(); 
}

From a comment over here:

function pointers dereference just fine, but the resulting function designator will be immediately converted back to a function pointer

And from an answer here:

Dereferencing (in way you think) a function's pointer means: accessing a CODE memory as it would be a DATA memory.

Function pointer isn't suppose to be dereferenced in that way. Instead, it is called.

I would use a name "dereference" side by side with "call". It's OK.

Anyway: C is designed in such a way that both function name identifier as well as variable holding function's pointer mean the same: address to CODE memory. And it allows to jump to that memory by using call () syntax either on an identifier or variable.

How exactly does dereferencing of a function pointer work?