xsl:variable does not return a node-set in XSLT 2.0?

Posted by Henry on Stack Overflow See other posts from Stack Overflow or by Henry
Published on 2010-05-08T06:36:39Z Indexed on 2010/05/08 6:48 UTC
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Hi all,

I'm trying to get a node-set from a xsl variable for calculating. But my code only work with Opera, with other browsers, I keep getting the error.

Please help me fix to run with all browser. Thanks in advance.

Here are the xslt code:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:output method="html"/>

<xsl:variable name="multipleSet">
 <xsl:for-each select="myNums/numSet">
  <xsl:element name="multiple"><xsl:value-of select="num1 * num2"/></xsl:element>
 </xsl:for-each>
</xsl:variable>
<xsl:template match="/">
 <table border="1">
    <tr>
     <th>Num 1</th>
     <th>Num 2</th>
     <th>Multiple</th>
    </tr>
   <xsl:for-each select="myNums/numSet">
    <tr>
     <td><xsl:value-of select="num1"/></td>
     <td><xsl:value-of select="num2"/></td>
     <td><xsl:value-of select="num1 * num2"/></td>
    </tr>
   </xsl:for-each>
    <tr>
     <th colspan="2" align="right">Total:</th>
     <td><xsl:value-of select="sum($multipleSet/multiple)"/> </td>
    </tr>
 </table>
</xsl:template>
</xsl:stylesheet>

And the xml:

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<myNums>
 <numSet>
  <num1>5</num1>
  <num2>5</num2>
 </numSet>
 <numSet>
  <num1>10</num1>
  <num2>5</num2>
 </numSet>
 <numSet>
  <num1>15</num1>
  <num2>20</num2>
 </numSet>
</myNums>

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