Hi all. I have a C++ project that uses a C bison parser. The C parser uses a struct of function pointers to call functions that create proper AST nodes when productions are reduced by bison:

typedef void Node;
struct Actions {
  Node *(*newIntLit)(int val);
  Node *(*newAsgnExpr)(Node *left, Node *right);
  /* ... */
};

Now, in the C++ part of the project, i fill those pointers

class AstNode {
  /* ... */
};
class IntLit : public AstNode { 
  /* ... */
};

extern "C" {
  Node *newIntLit(int val) {
    return (Node*)new IntLit(val);
  }

  /* ... */
}

Actions createActions() {
  Actions a;
  a.newIntLit = &newIntLit;
  /* ... */
  return a;
}

Now the only reason i put them within extern "C" is because i want them to have C calling conventions. But optimally, i would like their names still be mangled. They are never called by-name from C code, so name mangling isn't an issue. Having them mangled will avoid name conflicts, since some actions are called like error, and the C++ callback function has ugly names like the following just to avoid name clashes with other modules.

extern "C" {
  void uglyNameError(char const *str) {
    /* ... */
  }

  /* ... */
}

a.error = &uglyNameError;

I wondered whether it could be possible by merely giving the function type C linkage

extern "C" void fty(char const *str);
namespace {
  fty error; /* Declared! But i can i define it with that type!? */
}

Any ideas? I'm looking for Standard-C++ solutions.