I having a problem with the mysqli free() member function
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by neo skosana
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Published on 2010-05-09T11:26:11Z
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2010/05/09
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Hi
I have code where I connected to the database like so:
$db = new mysqli("localhost", "user", "pass", "company");
Now when I query the database like so:
//query calls to a stored procedure 'user_info'
$result = $db->query("CALL user_info('$instruc', 'c_register', '$eml', '$pass', '')");
//I use the $result
This query works well. Now when I try and free that result like so:
$result->free();
or
$result->close();
It seems like it doesn't do anything because $result
is still set. When I try to run another query it gives me this error:
Fatal error: Call to a member function fetch_array() on a non-object in...
For me to run this other query I have to close the db conection and connect again, then it will work. I want to know if there is a way I could run the other query without having to disconnect and reconnect to the database.
thanks in advance.
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