Javascript Prototyping Question

Posted by Nick Lowman on Stack Overflow See other posts from Stack Overflow or by Nick Lowman
Published on 2010-05-09T21:20:55Z Indexed on 2010/05/09 21:28 UTC
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I'm just reading about Prototypes in JavaScript and Douglas Crockford offers and excellent way to select a new objects prototype but can anyone explain (below) why obj01's type equals 'object' when I pass it in function as it's prototype?

if (typeof Object.beget !== 'function') {
     Object.beget = function (o) {
         console.log(typeof o);//function
         var F = function () {};
         F.prototype = o;
         console.log(typeof F);//function
         return new F();
     };
}
var func01 = function(){};
var obj01 = Object.beget(func01);
console.log(typeof obj01);//object
console.log(typeof obj01.prototype);//object

I thought it would be

console.log(typeof obj01);//function
console.log(typeof obj01.prototype);//function

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