Earlier I had ran puzzle where I asked question regarding size of index table for each index in database over here SQL SERVER – Size of Index Table – A Puzzle to Find Index Size for Each Index on Table. I had received good amount answers and I had blogged about that here SQL SERVER – Size of Index Table for Each Index – Solution. As a comment to that blog I have received another very interesting comment and that provides near accurate answers to original question. Many thanks to Rama Mathanmohan for providing wonderful solution.

SELECT
OBJECT_NAME(i.OBJECT_ID) AS TableName,
i.name AS IndexName,
i.index_id AS IndexID,
8 * SUM(a.used_pages) AS 'Indexsize(KB)'
FROM sys.indexes AS i
JOIN sys.partitions AS p ON p.OBJECT_ID = i.OBJECT_ID AND p.index_id = i.index_id
JOIN sys.allocation_units AS a ON a.container_id = p.partition_id
GROUP BY i.OBJECT_ID,i.index_id,i.name
ORDER BY OBJECT_NAME(i.OBJECT_ID),i.index_id

Let me know if you have any better script for the same.

Reference: Pinal Dave (http://blog.sqlauthority.com)