Putting a thread to sleep until event X occurs
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by tipu
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Published on 2010-05-10T02:52:22Z
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2010/05/10
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I'm writing to many files in a threaded app and I'm creating one handler per file. I have HandlerFactory class that manages the distribution of these handlers. What I'd like to do is that
thread A requests and gets foo.txt's file handle from the HandlerFactory class
thread B requests foo.txt's file handler
handler class recognizes that this file handle has been checked out
handler class puts thread A to sleep
thread B closes file handle using a wrapper method from HandlerFactory
HandlerFactory notifies sleeping threads
thread B wakes and successfully gets foo.txt's file handle
This is what I have so far,
def get_handler(self, file_path, type):
self.lock.acquire()
if file_path not in self.handlers:
self.handlers[file_path] = open(file_path, type)
elif not self.handlers[file_path].closed:
time.sleep(1)
self.lock.release()
return self.handlers[file_path][type]
I believe this covers the sleeping and handler retrieval successfully, but I am unsure how to wake up all threads, or even better wake up a specific thread.
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