Filtering most out of XML with XSL?

Posted by Gnudiff on Stack Overflow See other posts from Stack Overflow or by Gnudiff
Published on 2009-04-10T15:11:06Z Indexed on 2010/05/11 4:04 UTC
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I need to transform a lot of XML files (Fedora export) into a different kind of XML. Trying to do it with XSL stylesheets and checking with the msxsl transformer.

Supposedly I have xml file like this (assuming there are actually other nodes inside AAA, OBJ, amd all other nodes), Source.XML:

<DOC>
<AAA>
    <STUFF>example</STUFF>
    <OBJ>
        <OBJVERS id="A1" CREATED="2008-02-18T13:28:08.245Z"/>
        <OBJVERS id="A2" CREATED="2008-02-19T10:42:41.965Z"/>
        <OBJVERS id="A13" CREATED="2009-03-16T12:43:11.703Z"/>
    </OBJ>
</AAA>
<FFF/>
<GGG/>
<DDD>
    <FILE />
</DDD>
</DOC>

Which I need to look something like this (Target.XML):

    <MYOBJ>
      <ELEM>contents of OBJVERS with the biggest id OR 
creation date (whichever is easier to do) go here</ELEM>
      <IMAGE> contents of <FILE> node go here</IMAGE>
    </MYOBJ>

The main problem that I have is that since I am new to XSL (and for this particular task do not have enough time to learn it properly) is that I can't understand how to tell XSL processor not to process anything else, I keep getting output from , for example.

Update: basically, I solved this problem meanwhile. I will post my own answer and close the question.

Update2: OK, Andrew's answer works, too, so I am just accepting it. :)

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