In Python, urllib2 giving error
Posted
by pythBegin
on Stack Overflow
See other posts from Stack Overflow
or by pythBegin
Published on 2010-05-12T10:58:36Z
Indexed on
2010/05/12
11:04 UTC
Read the original article
Hit count: 344
I tried running this,
>>> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl')
But it is giving error like this, can anyone tell me a solution ?
Traceback (most recent call last):
File "<pyshell#11>", line 1, in <module>
urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl')
File "C:\Python26\lib\urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python26\lib\urllib2.py", line 391, in open
response = self._open(req, data)
File "C:\Python26\lib\urllib2.py", line 409, in _open
'_open', req)
File "C:\Python26\lib\urllib2.py", line 369, in _call_chain
result = func(*args)
File "C:\Python26\lib\urllib2.py", line 1161, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "C:\Python26\lib\urllib2.py", line 1136, in do_open
raise URLError(err)
URLError: <urlopen error [Errno 11001] getaddrinfo failed>
© Stack Overflow or respective owner