Echoing variable construct instead of content

Posted by danp on Stack Overflow See other posts from Stack Overflow or by danp
Published on 2010-05-13T14:10:16Z Indexed on 2010/05/13 14:14 UTC
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I'm merging two different versions of a translations array. The more recent version has a lot of changes, over several thousand lines of code.

To do this, I loaded and evaluated the new file (which uses the same structure and key names), then loaded and evaluated the older version, overwriting the new untranslated values in the array with the values we already have translated.

So far so good!

However, I want to be able to echo out the constructor for this new merged array so I can cut and paste it into the new translation file, and have job done (apart from completing the rest of the translations..).

The code looks like this (lots of different keys, not just index):

$lang["index"]["chart1_label1"] = "Subscribed";
$lang["index"]["chart1_label2"] = "Unsubscribed";

And the old..

$lang["index"]["chart1_label1"] = "Subscrito";
$lang["index"]["chart1_label2"] = "Não subscrito";

After loading the two files, I end up with a merged $lang array, which I then want to echo out in the same form, so it can be used by the project.

However, when I do something like this..

foreach ($lang as $key => $value) { 
    if (is_array($value)) {
        foreach ($value as $key2 => $value2) {
            echo "$lang['".$key."']"; // ... etc etc
        }
    }
}

..obviously I get "ArrayIndex" etc etc instead of "$lang". How to echo out $lang without it being evaluated..? Once this is working, can add in the rest of the brackets etc (I realise they are missing), but just want to make this part work first.

If there's a better way to do this, all ears too!

Thanks.

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