Organizing a random list of objects in Python.
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by Saebin
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Published on 2010-05-13T17:16:27Z
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2010/05/13
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So I have a list that I want to convert to a list that contains a list for each group of objects.
ie ['objA.attr1', 'objC', 'objA.attr55', 'objB.attr4'] would return [['objA.attr1', 'objA.attr55'], ['objC'], ['objB.attr4']]
currently this is what I use:
givenList = ['a.attr1', 'b', 'a.attr55', 'c.attr4']
trgList = []
objNames = []
for val in givenList:
obj = val.split('.')[0]
if obj in objNames:
id = objNames.index(obj)
trgList[id].append(val)
else:
objNames.append(obj)
trgList.append([val])
#print trgList
It seems to run a decent speed when the original list has around 100,000 ids... but I am curious if there is a better way to do this. Order of the objects or attributes does not matter. Any ideas?
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