Run web.py as daemon.
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by mamcx
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Published on 2009-07-07T16:51:24Z
Indexed on
2010/05/13
16:04 UTC
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python
|backgroundworker
I have a simple web.py program to load data. In the server I don't want to install apache or any webserver.
I try to put it as a background service with http://www.jejik.com/articles/2007/02/a_simple_unix_linux_daemon_in_python/
And subclassing: (from http://www.jejik.com/files/examples/daemon.py)
class Daemon:
def start(self):
"""
Start the daemon
"""
... PID CHECKS....
# Start the daemon
self.daemonize()
self.run()
#My code
class WebService(Daemon):
def run(self):
app.run()
if __name__ == "__main__":
if DEBUG:
app.run()
else:
service = WebService(os.path.join(DIR_ACTUAL,'ElAdministrador.pid'))
if len(sys.argv) == 2:
if 'start' == sys.argv[1]:
service.start()
elif 'stop' == sys.argv[1]:
service.stop()
elif 'restart' == sys.argv[1]:
service.restart()
else:
print "Unknown command"
sys.exit(2)
sys.exit(0)
else:
print "usage: %s start|stop|restart" % sys.argv[0]
sys.exit(2)
However, the web.py software not load (ie: The service no listen)
If I call it directly (ie: No using the daemon code) work fine.
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