is there a better way of replacing duplicates in a list (python)
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by myeu2
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Published on 2010-05-14T20:30:06Z
Indexed on
2010/05/14
20:34 UTC
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Given a list:
- l1:
['a', 'b', 'c', 'a', 'a', 'b']
- output:
['a', 'b', 'c', 'a'_1, 'a'_2, 'b'_1 ]
I created the following code to get the output. Its messyyy..
for index in range(len(l1)):
counter = 1
list_of_duplicates_for_item = [dup_index for dup_index, item in enumerate(l1) if item == l1[index] and l1.count(l1[index]) > 1]
for dup_index in list_of_duplicates_for_item[1:]:
l1[dup_index] = l1[dup_index] + '_' + str(counter)
counter = counter + 1
Is there a more pythonic way of doing this? I couldnt find anything on the web.
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