Why doesn't Java warn about a == "something"?
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by Marius
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Published on 2010-05-14T18:44:22Z
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2010/05/14
18:54 UTC
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java
|language-design
This might sound stupid, but why doesn't the Java compiler warn about the expression in the following if statement:
String a = "something";
if(a == "something"){
System.out.println("a is equal to something");
}else{
System.out.println("a is not equal to something");
}
I realize why the expression is untrue, but AFAIK, a can never be equal to the String literal "something". The compiler should realize this and at least warn me that I'm an idiot who is coding way to late at night.
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