Why doesn't Java warn about a == "something"?
Posted
by Marius
on Stack Overflow
See other posts from Stack Overflow
or by Marius
Published on 2010-05-14T18:44:22Z
Indexed on
2010/05/14
18:54 UTC
Read the original article
Hit count: 200
Filed under:
java
|language-design
This might sound stupid, but why doesn't the Java compiler warn about the expression in the following if statement:
String a = "something";
if(a == "something"){
System.out.println("a is equal to something");
}else{
System.out.println("a is not equal to something");
}
I realize why the expression is untrue, but AFAIK, a can never be equal to the String literal "something". The compiler should realize this and at least warn me that I'm an idiot who is coding way to late at night.
© Stack Overflow or respective owner
