Writing JSON with XSLT

Posted by JP on Stack Overflow See other posts from Stack Overflow or by JP
Published on 2010-05-14T21:41:59Z Indexed on 2010/05/14 23:34 UTC
Read the original article Hit count: 442

Filed under:
|

Hi, I'm trying to write XSLT to transform a specific web page to JSON. The following code demonstrates how Ruby would do this conversion, but the XSLT doesn't generate valid JSON (there's one too many commas inside the array) - anyone know how to write XSLT to generate valid JSON?

require 'rubygems'
require 'nokogiri'
require 'open-uri'

doc = Nokogiri::HTML(open('http://bbc.co.uk/radio1/playlist'))
xslt = Nokogiri::XSLT(DATA.read)

puts out = xslt.transform(doc)

# Now follows the XSLT
__END__
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml">
    <xsl:output method="text" encoding="UTF-8" media-type="text/plain"/>

    <xsl:template match="/">
        [
        <xsl:for-each select="//*[@id='playlist_a']//div[@class='artists_and_songs']//ul[@class='clearme']">
            {'artist':'<xsl:value-of select="li[@class='artist']" />','track':'<xsl:value-of select="li[@class='song']" />'},
        </xsl:for-each>
        ]
    </xsl:template>
</xsl:stylesheet>

© Stack Overflow or respective owner

Related posts about xslt

Related posts about JSON