Does this have anything to do with endian-ness?
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by eSKay
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Published on 2010-05-15T05:21:31Z
Indexed on
2010/05/15
5:34 UTC
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This piece of code:
#include<stdio.h>
void hello() { printf("hello\n"); }
void bye() { printf("bye\n"); }
int main() {
printf("%p\n", hello);
printf("%p\n", bye);
return 0;
}
output on my machine:
0x80483f4
0x8048408
[second address is bigger in value]
on Codepad
0x8048541
0x8048511
[second address is smaller in value]
Does this have anything to do with endian-ness of the machines? If not,
Why the difference in the ordering of the addresses?
Also, Why the difference in the difference?
0x8048541 - 0x8048511 = 0x30
0x8048408 - 0x80483f4 = 0x14
Btw, I just checked. This code (taken from here) says that both the machines are Little-Endian
#include<stdio.h>
int main() {
int num = 1;
if(*(char *)&num == 1)
printf("Little-Endian\n");
else
printf("Big-Endian\n");
return 0;
}
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