How to call an xslt transform into an xsl stylesheet

Posted by Mycol on Stack Overflow See other posts from Stack Overflow or by Mycol
Published on 2010-05-15T14:38:47Z Indexed on 2010/05/15 14:44 UTC
Read the original article Hit count: 218

Filed under:

I have written an xslt that reads some xml file names and does some operations on them.
I use a for-each to work them one-by-one. I have each path inside a parameter $path.

But now I would like to output the result of applying an external stylesheet to those files. I would write something like

<div> <something like xsl-transform($extern-xslt,$path)> </div>

to have the result tree of the transformation inside the main html output. It is possible?

© Stack Overflow or respective owner

Related posts about xslt