How to call an xslt transform into an xsl stylesheet
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Published on 2010-05-15T14:38:47Z
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2010/05/15
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xslt
I have written an xslt that reads some xml file names and does some operations on them.
I use a for-each to work them one-by-one. I have each path inside a parameter $path.
But now I would like to output the result of applying an external stylesheet to those files. I would write something like
<div> <something like xsl-transform($extern-xslt,$path)> </div>
to have the result tree of the transformation inside the main html output. It is possible?
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