Determine calling executable in Python
Posted
by Brian Rosner
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Published on 2010-05-17T02:58:59Z
Indexed on
2010/05/17
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python
I am trying to find the best way of re-invoking a Python script within itself. Currently it is working like http://github.com/benoitc/gunicorn/blob/master/gunicorn/arbiter.py#L285. The START_CTX
is created at http://github.com/benoitc/gunicorn/blob/master/gunicorn/arbiter.py#L82-86.
The code is relying on sys.argv[0]
as the "caller". However, this fails in cases where it is invoked with:
python script.py ...
This case does work:
python ./script.py ...
because the code uses os.chdir
before running os.execlp
.
I did notice os.environ["_"]
, but I am not sure how reliable that would be. Another possible case is to check if sys.argv[0]
is not on PATH
and is not executable and use sys.executable
when calling os.execlp
.
Any thoughts on a better approach solving this issue?
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