Determine calling executable in Python

Posted by Brian Rosner on Stack Overflow See other posts from Stack Overflow or by Brian Rosner
Published on 2010-05-17T02:58:59Z Indexed on 2010/05/17 3:00 UTC
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I am trying to find the best way of re-invoking a Python script within itself. Currently it is working like http://github.com/benoitc/gunicorn/blob/master/gunicorn/arbiter.py#L285. The START_CTX is created at http://github.com/benoitc/gunicorn/blob/master/gunicorn/arbiter.py#L82-86.

The code is relying on sys.argv[0] as the "caller". However, this fails in cases where it is invoked with:

python script.py ...

This case does work:

python ./script.py ...

because the code uses os.chdir before running os.execlp.

I did notice os.environ["_"], but I am not sure how reliable that would be. Another possible case is to check if sys.argv[0] is not on PATH and is not executable and use sys.executable when calling os.execlp.

Any thoughts on a better approach solving this issue?

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