How do I translate a ISO 8601 datetime string into a Python datetime object?
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by Andrey Fedorov
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Published on 2009-06-09T10:36:34Z
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2010/05/17
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I'm getting a datetime string in a format like "2009-05-28T16:15:00" (this is ISO 8601, I believe) one hack-ish option seems to be to parse the string using time.strptime
and passing the first 6 elements of the touple into the datetime constructor, like:
datetime.datetime(*time.strptime("2007-03-04T21:08:12", "%Y-%m-%dT%H:%M:%S")[:6])
I haven't been able to find a "cleaner" way of doing this, is there one?
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