PHP use function return value as array
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by Richard Knop
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Published on 2010-05-17T17:57:33Z
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2010/05/17
18:00 UTC
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Why is it that this works:
$cacheMatchesNotPlayed = $cache->load('externalData');
$cacheMatchesNotPlayed = $cacheMatchesNotPlayed['matchesNotPlayed'];
But this doesn't work:
$cacheMatchesNotPlayed = $cache->load('externalData')['matchesNotPlayed'];
Is there some reason for it? The second bit is easier to write.
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