Why address of a variable change after each execution in C?

Posted by Mohit on Stack Overflow See other posts from Stack Overflow or by Mohit
Published on 2010-05-17T04:17:15Z Indexed on 2010/05/17 4:20 UTC
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int i=10; printf("Address of i = %u",&i);

Output: Address if i = 3220204848

Output on re-execution: Address of i = 3216532594

I get a new address of i each time I execute the program. What does this signify?

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Why address of a variable change after each execution in C? - Developer IT

Why address of a variable change after each execution in C?

c

pointers

programming-languages

Related posts about c

Related posts about pointers

C++ smart pointers: sharing pointers vs. sharing data

handling refrence to pointers/double pointers using SWIG [C++ to Java]

char pointers & integer pointers (++)

Smart pointers - cases where they cannot replace raw pointers

C++ Pointers: Number of levels of Indirection

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