Get filename from path
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by Eric
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Published on 2010-05-18T16:10:13Z
Indexed on
2010/05/18
16:31 UTC
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perl
I am trying to parse the filename from paths. I have this:
my $filepath = "/Users/Eric/Documents/foldername/filename.pdf";
$filepath =~ m/^.*\\(.*[.].*)$/;
print "Linux path:";
print $1 . "\n\n";
print "-------\n";
my $filepath = "c:\\Windows\eric\filename.pdf";
$filepath =~ m/^.*\\(.*[.].*)$/;
print "Windows path:";
print $1 . "\n\n";
print "-------\n";
my $filepath = "filename.pdf";
$filepath =~ m/^.*\\(.*[.].*)$/;
print "Without path:";
print $1 . "\n\n";
print "-------\n";
But that returns:
Linux path:
-------
Windows path:Windowsic
ilename.pdf
-------
Without path:Windowsic
ilename.pdf
-------
I am expecting this:
Linux path:
filename.pdf
-------
Windows path:
filename.pdf
-------
Without path:
filename.pdf
-------
Can somebody please point out what I am doing wrong?
Thanks! :)
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