How to: generate UnhandledException?
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by serhio
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Published on 2010-05-18T21:59:04Z
Indexed on
2010/05/18
22:20 UTC
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I use this code to catch the WinForm application UnhandledException.
[STAThread]
static void Main(string[] args)
{
// Add the event handler for handling UI thread exceptions to the event.
Application.ThreadException += new
System.Threading.ThreadExceptionEventHandler(Application_ThreadException);
// Set the unhandled exception mode to force all Windows Forms errors
// to go through our handler.
Application.SetUnhandledExceptionMode(UnhandledExceptionMode.CatchException);
// Add the event handler for handling non-UI thread exceptions to the event.
AppDomain.CurrentDomain.UnhandledException +=
new UnhandledExceptionEventHandler(CurrentDomain_UnhandledException);
try
{
Application.Run(new MainForm());
} catch....
There I will try to restart the application. Now my problem is to simulate a exception like this. I tried before try (in main): throw new NullReferenceException("test");
VS caught it.
Tried also in MainForm code with button :
private void button1_Click(object sender, EventArgs ev)
{
ThreadPool.QueueUserWorkItem(new WaitCallback(TestMe), null);
}
protected void TestMe(object state)
{
string s = state.ToString();
}
did not help, VS caught it, even in Release mode.
- How should I, finally, force the application generate UnhandleldException?
- Will I be able to restart the application in
CurrentDomain_UnhandledException
?
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