How to make a tree view from MySQL and PHP and jquery

Posted by Mac Taylor on Stack Overflow See other posts from Stack Overflow or by Mac Taylor
Published on 2010-05-18T13:31:12Z Indexed on 2010/05/18 13:50 UTC
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hey guys

i need to show a treeview of my categories , saved in my mysql database .

Database table :

table : cats :

columns: id,name,parent

Here is a sample of what I want the markup to be like:

<ul id="browser" class="filetree">
  <li><span class="folder">Folder 1</span>
   <ul>
    <li><span class="file">Item 1.1</span></li>
   </ul>
  </li>
  <li><span class="folder">Folder 2</span>
   <ul>
    <li><span class="folder">Subfolder 2.1</span>
     <ul id="folder21">
      <li><span class="file">File 2.1.1</span></li>
      <li><span class="file">File 2.1.2</span></li>
     </ul>
    </li>
    <li><span class="file">File 2.2</span></li>
   </ul>
  </li>
  <li><span class="file">File 4</span></li>
 </ul>

i used this script to show treeview : http://www.dynamicdrive.com/dynamicindex1/treeview

now problem is in php part :

//function to build tree menu from db table test1
function tree_set($index)
{
    global $menu;
    $q=mysql_query("select * from cats where parent='$index'");
    if(!mysql_num_rows($q))
        return;
    $menu .= '<ul>'."\n";
    while($arr=mysql_fetch_assoc($q))
    {
        $menu .= '<li>';
        $menu .= '<span class="file">'.$arr['name'].'</span>';//you can add another output there
        $menu .=tree_set("".$arr['id']."");
        $menu .= '</li>'."\n";
    }

    $menu.= '</ul>'."\n";
return $menu;

}



//variable $menu must be defined before the function call
 $menu = '
 <link rel="stylesheet" href="modules/Topics/includes/jquery.treeview.css" />
 <script src="modules/Topics/includes/lib/jquery.cookie.js" type="text/javascript"></script>
 <script src="modules/Topics/includes/jquery.treeview.js" type="text/javascript"></script>
 <script type="text/javascript" src="modules/Topics/includes/demo/demo.js"></script>
 <ul id="browser" class="filetree">'."\n";
 $menu .= tree_set(0);
 $menu .= '</ul>';
echo $menu;  

i even asked in this forum : http://forums.tizag.com/showthread.php?p=60649

problem is in php part of my codes that i mentioned . i cant show sub menus , i mean , really i dont know how to show sub menus

is there any chance of a pro php coder helping me here ?

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