Why isn't the boost::shared_ptr -> operator inlined?
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by Alan
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Published on 2010-05-18T14:38:52Z
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2010/05/18
15:20 UTC
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Since boost::shared_ptr could be called very frequently and simply returns a pointer, isn't the -> operator a good candidate for being inlined?
T * operator-> () const // never throws
{
BOOST_ASSERT(px != 0);
return px;
}
Would a good compiler automatically inline this anyway?
Should I lose any sleep over this? :-)
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