Haskell: Gluing a char and a list together?

Posted by Vincent on Stack Overflow See other posts from Stack Overflow or by Vincent
Published on 2010-05-19T15:11:41Z Indexed on 2010/05/19 15:30 UTC
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So I have this code here:

toWords :: String -> [a] toWords "" = [] toWords (nr1 : rest) | nr1 == ' ' = toWords rest | otherwise = nr1 : toWords rest

The "toWords" function should simply remove all spaces and return a list with all the words. But I keep getting this error:

test.hs:5:18: Couldn't match expected type a' against inferred typeChar'

  `a' is a rigid type variable bound by
      the type signature for `toWords' at test.hs:1:22
In the first argument of `(:)', namely `nr1'
In the expression: nr1 : toWords rest
In the definition of `toWords':
    toWords (nr1 : rest)
              | nr1 == ' ' = toWords rest
              | otherwise = nr1 : toWords rest Failed, modules loaded:

none.

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