Mysql: Order Results by number of matching rows in Second Table.
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by KyleT
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Published on 2010-05-19T20:59:22Z
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2010/05/19
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mysql
I'm not sure the best way to word this question so bear with me.
Table A has following columns:
- id
- name
- description
Table B has the following columns:
- id
- a_id(foreign key to Table A)
- ip_address
- date
Basically Table B contains a row for each time a user views a row from Table A.
My question is how do I sort Table A results, based on the number of matching rows in Table B.
i.e
SELECT *
FROM TableA
ORDER BY (SELECT COUNT(*)
FROM TableB
where TableB.a_id = TableA.id)
Thank you!
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