Unboxing to unknown type
Posted
by Robert
on Stack Overflow
See other posts from Stack Overflow
or by Robert
Published on 2010-05-19T20:15:56Z
Indexed on
2010/05/19
20:20 UTC
Read the original article
Hit count: 314
c#
|inferred-type
I'm trying to figure out syntax that supports unboxing an integral type (short/int/long) to its intrinsic type, when the type itself is unknown.
Here is a completely contrived example that demonstrates the concept:
// Just a simple container that returns values as objects struct DataStruct { public short ShortVale; public int IntValue; public long LongValue; public object GetBoxedShortValue() { return LongValue; } public object GetBoxedIntValue() { return LongValue; } public object GetBoxedLongValue() { return LongValue; } }
static void Main( string[] args ) {
DataStruct data;
// Initialize data - any value will do data.LongValue = data.IntValue = data.ShortVale = 42;
DataStruct newData;
// This works if you know the type you are expecting! newData.ShortVale = (short)data.GetBoxedShortValue(); newData.IntValue = (int)data.GetBoxedIntValue(); newData.LongValue = (long)data.GetBoxedLongValue();
// But what about when you don't know? newData.ShortVale = data.GetBoxedShortValue(); // error newData.IntValue = data.GetBoxedIntValue(); // error newData.LongValue = data.GetBoxedLongValue(); // error }
In each case, the integral types are consistent, so there should be some form of syntax that says "the object contains a simple type of X, return that as X (even though I don't know what X is)". Because the objects ultimately come from the same source, there really can't be a mismatch (short != long).
I apologize for the contrived example, it seemed like the best way to demonstrate the syntax.
Thanks.
© Stack Overflow or respective owner