I'm attempting to upload a file like this:

import pycurl

c = pycurl.Curl()

values = [
     ("name", "tom"),
     ("image", (pycurl.FORM_FILE, "tom.png"))
]

c.setopt(c.URL, "http://upload.com/submit")
c.setopt(c.HTTPPOST, values)
c.perform()
c.close()

This works fine. However, this only works if the file is local. If I was to fetch the image such that:

import urllib2
resp = urllib2.urlopen("http://upload.com/people/tom.png")

How would I pass resp.fp as a file object instead of writing it to a file and passing the filename? Is this possible?