Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu

now there is not problem while creating submenu inside another submenu

now this is way I fetch the submenu for the top menu

<ul class="topmenu">
    <? $list = $obj -> childmenu($parentid); 
        //this list contains the array of submenu under $parendid
        foreach($list as $menu) {
            extract($menu);
            echo '<li><a href="#">'.$name.'</a></li>';
        }
    ?>
</ul>

What I want to do is.

• I want to check if a new menu has other child menu
• and I want to keep on checking until it searches every child menu that is available

• and I want to display its child menu inside its particular list item like this

• Home ........