libiconv - iconv_open() default behavior?

Posted by DooriBar on Stack Overflow See other posts from Stack Overflow or by DooriBar
Published on 2010-05-20T12:41:15Z Indexed on 2010/05/20 14:10 UTC
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iconv

According to the documentation of iconv_open() over: http://www.gnu.org/software/libiconv/documentation/libiconv/iconv_open.3.html

"//TRANSLIT" means that when a character cannot be represented in the target character set, it can be approximated through one or several characters.

and:

"//IGNORE" means that characters that cannot be represented in the target character set will be silently discarded.

But what is the default behavior, when neither are specified?

Thanks, Doori Bar

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Developer IT

libiconv - iconv_open() default behavior? - Developer IT

libiconv - iconv_open() default behavior?

iconv

Related posts about iconv

iconv supports too few encoding

Ruby Iconv works with irb and ruby debugger but not in a unit test

How to fix weird issue with iconv on Mac Os x

Call iconv from Ruby through system()

How do I remove accents from characters in a PHP string?

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