Android - I can't make a widget clickable to launch an intent
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by Daniele
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Published on 2010-05-23T21:48:32Z
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2010/05/23
21:50 UTC
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android
Hi all. I am new to Android development.
I have developed a very simple widget that was meant to interact with the user via an ImageButton.
What I am trying to do now is as follows. When a user taps the button (after adding the widget to their home screen), I want the phone to dial a certain telephone number. A sort of speed dial for your home screen.
Unfortunately when I tap the button nothing happens.
This is the body of my SpeedDialAppWidgetProvider.onUpdate method:
Log.d("", "beginning of onUpdate");
final int N = appWidgetIds.length;
for (int i=0; i<N; i++) {
int appWidgetId = appWidgetIds[i];
Log.d("", "dealing with appWidgetId: " + appWidgetId);
// Create an Intent to launch ExampleActivity
Intent dialIntent = new Intent(Intent.ACTION_CALL, Uri.parse("tel:1234567"));
PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, dialIntent, 0);
Log.d("", "pendingIntent classname " + pendingIntent.getClass().getName());
// Get the layout for the App Widget and attach an on-click listener to the button
RemoteViews remoteViews = new RemoteViews(context.getPackageName(), R.layout.speed_dial_appwidget);
remoteViews.setOnClickPendingIntent(R.id.dial_icon, pendingIntent);
Log.d("", "remoteViews classname " + remoteViews.getClass().getName());
// Tell the AppWidgetManager to perform an update on the current App Widget
appWidgetManager.updateAppWidget(appWidgetId, remoteViews);
Log.d("", "end of onUpdate");
I can see the method is called and the result of the logging makes sense.
The speed_dial_appwidget.xml file is like this:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
androidrientation="vertical"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
>
<ImageButton id="@+id/dial_icon"
android:src="@drawable/speed_dial"
android:layout_width="wrap_content"
android:layout_height="wrap_content"/>
</LinearLayout>
Can you please help me with this?
Thanks in advance, Dan
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