Scala parser combinators: how to parse "if(x)" if x can contain a ")"

Posted by Germán on Stack Overflow See other posts from Stack Overflow or by Germán
Published on 2010-05-23T21:12:48Z Indexed on 2010/05/23 21:21 UTC
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parser-combinators

I'm trying to get this to work:

def emptyCond: Parser[Cond] = ("if" ~ "(") ~> regularStr <~ ")" ^^ { case s => Cond("",Nil,Nil) }

where regularStr is defined to accept a number of things, including ")". Of course, I want this to be an acceptable input: if(foo()). But for any if(x) it is taking the ")" as part of the regularStr and so this parser never succeeds.

What am I missing?

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