Python - Checking for membership inside nested dict

Posted by victorhooi on Stack Overflow See other posts from Stack Overflow or by victorhooi
Published on 2010-05-25T03:45:15Z Indexed on 2010/05/25 3:51 UTC
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heya,

This is a followup questions to this one:

http://stackoverflow.com/questions/2901422/python-dictreader-skipping-rows-with-missing-columns

Turns out I was being silly, and using the wrong ID field.

I'm using Python 3.x here.

I have a dict of employees, indexed by a string, "directory_id". Each value is a nested dict with employee attributes (phone number, surname etc.). One of these values is a secondary ID, say "internal_id", and another is their manager, call it "manager_internal_id". The "internal_id" field is non-mandatory, and not every employee has one.

(I've simplified the fields a little, both to make it easier to read, and also for privacy/compliance reasons).

The issue here is that we index (key) each employee by their directory_id, but when we lookup their manager, we need to find managers by their "internal_id".

Before, when employee.keys() was a list of internal_ids, I was using a membership check on this. Now, the last part of my if statement won't work, since the internal_ids is part of the dict values, instead of the key itself.

def lookup_supervisor(manager_internal_id, employees):
    if manager_internal_idis not None and manager_internal_id!= "" and manager_internal_id in employees.keys():
        return (employees[manager_internal_id]['mail'], employees[manager_internal_id]['givenName'], employees[manager_internal_id]['sn'])
    else:
        return ('Supervisor Not Found', 'Supervisor Not Found', 'Supervisor Not Found')

So the first question is, how do I check whether the manager_internal_id is present in the dict's values.

I've tried substituting employee.keys() with employee.values(), that didn't work. Also, I'm hoping for something a little more efficient, not sure if there's a way to get a subset of the values, specifically, all the entries for employees[directory_id]['internal_id'].

Hopefully there's some Pythonic way of doing this, without using a massive heap of nested for/if loops.

My second question is, how do I then cleanly return the required employee attributes (mail, givenname, surname etc.). My for loop is iterating over each employee, and calling lookup_supervisor. I'm feeling a bit stupid/stumped here.

def tidy_data(employees):
    for directory_id, data in employees.items():
        # We really shouldnt' be passing employees back and forth like this - hmm, classes?
        data['SupervisorEmail'], data['SupervisorFirstName'], data['SupervisorSurname'] = lookup_supervisor(data['manager_internal_id'], employees)

Thanks in advance =), Victor

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